1) Introductions for the heat and mass transfer

Why the mechanical engineer should know how the heat and mass is transferred? for mechanical engineers, it is essential for them to analyze:

However, we don’t know exactly what concept we need to take the heat and mass transfer. So, let us talk together what preliminaries are in need.

More detailed concepts would be found in thermodynamics post, so we just remind the things briefly.

1. Nomenclatures

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Fig. 1. How the conduction, convection and radiation occurs - brief diagram

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Fig. 2. Topics of transport phenomena

Brief concepts of each the conduction, convection and radiation are below:

2. Conduction

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Fig. 3. Association of conduction heat transfer with diffusion of energy (molecular)

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Fig. 4. 1-dimensional heat transfer
3. Convection

Due to random molecular motion and (diffusion), energy is also transferred by the bulk, or macroscopic, motion of the fluid.

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Fig. 5. Boundary layer development in convection heat transfer.
4. Radiation

Energy emitted by matter that is at a nonzero temperature. Regardless of the form of matter, the emission may be attributed to changes in the electron configurations of the constituent atoms or molecules. The radiation rate equation is below:

where $q\prime\prime_{rad}$: the rate of radiation, $E_b$: the emissive power of a body $\epsilon$: emissivity of a gray body, such $0≤\epsilon≤$1, $\sigma$: Stefan Boltzman Constant $(\sigma\,=\,5.67\,\times\,10^{-8}\,W/m^2\,\cdot\,K)$, $G_{abs}\,=\alpha\,G$ where $\alpha\,=\,$absoptity, $0≤\alpha≤1$. Let me explain each single term.

Firstly, the emissive power in ‘ideal’ case is $E_b\,=\,\sigma\,T_s^4$. This is the consideration of black body, and the real emissive power is that of gray body, which is smaller emissive power than that of black body. To make up this differences, the quantity named of “emissivity” is applied, so this is the change: $E\,=\,\epsilon \sigma T_s^4$.

Secondly, let’s talk about the [Fig. 6.] Surface doesn’t absorb a whole radiation. it reflects the radiation, so this phenomena is called as “irradiation”. A portion of the irradiation may be absorbed by the surface. To find out the net rate of the radiation, it must also be considered. the absorbed quantity of irraditation is like: $G_{abs}\,=\,\alpha\,G$

Combining these two term, the above net rate equation is constructed.

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Fig. 6. Radiation Exchange

From now on, we’ll study three forms of heat transfer more deeply. Hope that this material would be help for your journey to the heat and mass transfer.


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